passing 2 dimenisional array to function

[arironen]

how is it done?!

[reinkesm]

I don't think passing a double array should be any different than passing any other variable.

public void method1() {
	int[][] myArr = new int[5][5];

	method2(myArr);
}

public void method2(int[][] anArr) {
	// work with array
}

[cjard]

Originally posted by arironen
how is it done?!

in java, we call them methods.. are you a c programmer? in java, the array pointers are handled for you.. just use their name as a reference to the whole array, and make sure the types are consistent

public void myMethod(TYPE NAME, TYPE2 NAME2, TYPE3 NAME3... etc ...)

so a 5 dimensional array of ints is:

int[][][][][] the5D....

and to pass it to a method:

public void methodTakes5DArray(int[][][][][] fiveDim){
}

note that arrays can be stripped of their dimension, as a 5D array can be thought of as an array of 4Dimensional arrays:

//declare an array of ten, 4D arrays:
int[][][][][] the5D = new int[10][][][][];

public void methodTakesA4DArray(int[][][][] the4D){
...
}

and elsewhere:
for(int i=0; i<10; i++){  //better to write i<the5D.length
  //call the 4D method
  methodTakesA4DArray(the5D[i]);
}

[arironen]

Thank you for the replies, it seems i was calling the function(method ) from a static contex(public void static main), since i wasnt using any classes i just made the function static. Thanks again for the replies.

ps: yes, i have programmed in c and my only complaint about java is it making me type out boolean instead of bool and the lack of #define, other than that i love java