dealing with large numbers

[savagecabbage]

Hi,
I'm supposed to calculate some rediculously large numbers (like 46^75). I know these numbers are definitely way beyond the capacity of doubles. Can anyone suggest a variable type to do that? Thanks.

[Sportsdude11751]

instead of double, use long. ex:
long a=watever

[Drain]

That isn't quite long enough

BigDecimal d = new BigDecimal(Math.pow(46,75));

50914018510357733692393581562939574405608588594976882332374683237310907296616337
624639423841109727047053358355569614346256384

[savagecabbage]

Drain,
Thanks a bunch! Now another question is how do I raise this number to the power of 1/75? I know this sounds stupid, but my project requires such silly computations. so I need to do
(46^75)^(1/75), which will be 46 again. I know that BigInteger has a function called pow() but it only takes int. Any idea?

[Drain]

Well, n^(1/a) is equivalent to the a root of n. Unfortunately, BigInteger doesn't have a method for that either... I'm not sure how you would do that.

[cjard]

http://www.merriampark.com/bigsqrt.htm