-
Problems with else if (URGENT)
Does anybody know what is causing errors i this code
class grades{
public static void main(String args[]){
double grade = Double.valueOf(args[0]);
String letterg;
if(grade==0)
{letterg = "F";}
else if((grade>0)&&grade<0.5)
{letterg = "D-";}
else if(((grade)=>0.5)&&grade<1.0)
{letterg = "D";}
else if((grade=>1.0)&&grade<1.5)
{letterg = "D+";}
else if((grade>1.5)&&grade<2.0)
{letterg = "C-";}
else if(grade==2.0)
{letterg = "C";}
else if((grade>2.0)&&grade<2.5)
{letterg = "C+";}
else if((grade=>2.5)&&grade<3.0)
{letterg = "B-";}
else if(grade==3.0)
{letterg = "B";}
else if((grade>3.0)&&grade<3.5))
{letterg = "B+";}
else if((grade=>3.5)&&grade<4.0)
{letter ="A";}
else
{letter ="Invalid number!"}
System.out.println("Your grade is"+letter);
}
}
Whenever i try to complie this I get:
grades.java:10: illegal start of expression
else if(((grade)=>0.5)&&grade<1.0)
^
grades.java:31: ')' expected
System.out.println("Your grade is"+letter);
-
Hi Wizard,
there was quite a few bits wrong with it, the main ones are that greater than or equal to is >= in java not =>
few wrong var names, a missing semi colon, and I think you mean to use parseDouble rather than valueof,
The corrected code is below - hope this helps.
Graham
-------------------------------------------
class grades{
public static void main(String args[]){
double grade = Double.parseDouble(args[0]);
String letterg;
if(grade==0)
{letterg = "F";}
else if((grade>0)&&grade<0.5)
{letterg = "D-";}
else if(((grade)>=0.5)&&grade<1.0)
{letterg = "D";}
else if((grade>=1.0)&&grade<1.5)
{letterg = "D+";}
else if((grade>1.5)&&grade<2.0)
{letterg = "C-";}
else if(grade==2.0)
{letterg = "C";}
else if((grade>2.0)&&grade<2.5)
{letterg = "C+";}
else if((grade>=2.5)&&grade<3.0)
{letterg = "B-";}
else if(grade==3.0)
{letterg = "B";}
else if((grade>3.0)&&(grade<3.5))
{letterg = "B+";}
else if((grade>=3.5)&&grade<4.0)
{letterg ="A";}
else
{letterg ="Invalid number!";}
System.out.println("Your grade is"+letterg);
}
}
-
Thank you very much, I finally got this to compile.
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