Easy for Loop Problem


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Thread: Easy for Loop Problem

  1. #1
    Join Date
    Oct 2004
    Posts
    1

    Easy for Loop Problem

    Hello all,

    I have stumbled on a programming exercise and am in need of a little help.

    Problem: Get an integer n from an input dialog, print out the following pattern on the console window.

    For example, when n is 3, there are 5 (2 * n - 1 = 2 * 3 -1 = 5) rows in total:

    example: http://david.vonetwork.net/pattern1.bmp

    For another example, when n is 4 there are 7 (2 * n -1=2 * 4 -1 = 7) rows in total:


    Example 2: http://david.vonetwork.net/pattern2.bmp

    I know how to get n from an integer dialog box, but I am stuck in making the patterns. It is required that you use only nested for loops.

    The Reward

    I am unable to make this a paid project but I am offering 6 g-mail accounts for the correct solution

    This should be a simple exercise for any experienced java programming. If you would like to help me out just post the solution either in this thread or in a pm.

    Thanks for your help in advance,
    Joe

    PS. This post is going be posted on multiple forums, first one overall to get the correct solution gets the g0mail accounts. I will of course update you on the status
    Last edited by iidavidii; 10-18-2004 at 01:17 AM.

  2. #2
    Join Date
    May 2004
    Location
    Durham, UK
    Posts
    174
    Hi,

    heres my little effort at it.

    Cheers
    Graham

    ----------------------------------------------------------------
    Code:
    public class OutputPattern
    {
        
        public static void main(String[] args)
        {
            OutputPattern op = new OutputPattern();
            try
            {
                op.doWork();
            }catch(java.io.IOException ioe)
            {
                System.out.println("Got Exception" + ioe);
            }
        }
        
        public void doWork() throws java.io.IOException
        {
            // Assume that this has be read in
            
            int NumberofIterations = Integer.parseInt(System.in.read()+"" ) - 48;
                  
            
            for(int i = 1; i <= (2 *NumberofIterations - 1); i+=2)
            {
                // Print spacers
                
                for(int spacer=0; spacer < (NumberofIterations - (i/2)); spacer++)
                {
                    System.out.print(" ");
                }
    
                // print stars
                
                for(int stars = 0; stars < i; stars++)
                {
                    System.out.print("*");
                }
                System.out.println("");
            }
    
            // Now do it in reverse
            
            for(int i = (2 * NumberofIterations - 3); i >= 1; i-=2)
            {
                // Print spacers
                
                for(int spacer=0; spacer < (NumberofIterations - (i/2)); spacer++)
                {
                    System.out.print(" ");
                }
    
                // print stars
                
                for(int stars = 0; stars < i; stars++)
                {
                    System.out.print("*");
                }
                System.out.println("");
            }
        }
    }
    Last edited by JGRobinson; 10-27-2004 at 04:59 PM.
    Hope this helps
    Graham

    Before you criticize someone, you should walk a mile in their shoes. That way, when you criticize them, and if they get mad, you are a mile away and you have their shoes ;-)

    http://www.grahamrobinsonsoftware.com

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