
ExpX? How is the math done?
The following is what my output has to be. Well, minus the numbers obviously. I have to enter an integer for x, than n and than get an answer. Now, I'm really confused. How exactly is the math done? If I enter 5 for x and 6 for n, how do I get 26.041666?
[phpsComputer:~] php% javac ExpX.java
[phpsComputer:~] php% java ExpX
enter an integer for x: 5
enter an integer for n: 6
E(5) using n =6 terms is: 26.041666666666668
[phpsComputer:~] php% java ExpX
enter an integer for x: 34
enter an integer for n: 3
E(34) using n =3 terms is: 578.0
[phpsComputer:~] php% java ExpX
enter an integer for x: 12
enter an integer for n: 9
E(12) using n =9 terms is: 10664.228571428572
[phpsComputer:~] php% java ExpX
enter an integer for x: 5
enter an integer for n: 4
service not available
[phpsComputer:~] php% java ExpX
enter an integer for x: 3
enter an integer for n: 6
E(3) using n =6 terms is: 2.025

Definition of e
Exponential function
Here is what Java's exp method does:
static double exp(double a)
Returns Euler's number e raised to the power of a double value.
Without the code it's impossible to say what yours is doing. My guess is your program is calculating 'E' using varying degrees of accuracy (with variable n). Normally you would expect them to raise 'x' to the E power. Where E is calculated to the 'n'th accuracy.
When I tested it though with your examples, the results didn't match up. So, in short, without the code it's just guessing.
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