String Tokenizer

[balan]

Hello experts,
I have some text which contains 30 characters that is stored in a variable. I am reading those text using tokenizer. I want to display these 30 characters in 3 lines. 10 characters in each line. How to identify and print each 10 characters. my coding is as follows...

class file2{

public static void main(String[] args) throws IOException {

String st1="You may choose an icon for you";

StringTokenizer st = new StringTokenizer(st1,"10");
while (st.hasMoreTokens())
{
System.out.println(st.nextToken());
}

Thank you

Balen

[smcneill]

class file2{

public static void main(String[] args) throws IOException {

   String st1="You may choose an icon for you";
   // If you know the string length is constant e.g: 30
   // you don't need an iterator.
   System.out.println(st1.substring(0, 10)); // Returns chars 0 through 9
   System.out.println(st1.substring(10, 20)); // Returns chars 10 through 19
   System.out.println(st1.substring(20)); //Returns chars 20 to end
   
   
   StringTokenizer st = new StringTokenizer(st1,"10");
   while (st.hasMoreTokens()) {
      System.out.println(st.nextToken());
   } 
}

[gwoods]

StringTokenizer st = new StringTokenizer("Hello java");
while (st.hasMoreTokens()) {
System.out.println(st.nextToken());
}
prints the following output:

Hello
java

Please see full description here http://www.developerzone.biz/index.p...d=89&Itemid=36

[evlich]

StringTokenizer won't do this for you (unless there is something that I don't know about it), you will need to do it manuall like smcneill suggested. If you don't know its a constant size then you can simply do it in a loop. If you don't want to break the string in the middle of words then you can do something a little bit more complicated with StringTokenizer.

StringTokenizer st = new StringTokenizer(string);
int curCount = 0;
String current;
while( st.hasMoreTokens() ) {
  current = st.nextToken();
  if( curCount + current.length() < 10 || curCount == 0 ) {
    System.out.print(current + " ");
    curCount += current.length() + 1;
  } else {
    System.out.println();
    System.out.print(current + " ");
    curCount = current.length() + 1;
  }
  if( curCount > 10 ) {
    curCount = 0;
    System.out.println();
  }
}

Hope this helps.