the problem is for me to compute and approxiamte value for euler's constant by summing the series (adding up the terms 1, 1/2, ...., 1/n in that order and then subtracting the value fo In(n)).
I have to do this with both double and float arithmetic.

Here is what I have so far.

public class PP2 {
public static void main(String[] args) throws

IOException {
System.out.println("Enter the limit for sum:");
BufferedReader kbd = new BufferedReader(new

String S = kbd.readLine();
int loops = Integer.parseInt(S.trim());
int n;
for (n = 1; n <= loops; n++)
double sum = sum + (double)(1/n);
float sum2 = sum2 + (float)(1/n);
double condoub = sum - (double)Math.log(loops);
float conflout = sum2 - (float)Math.log(loops);
System.out.println("Euler's const, double: =" + condoub);
System.out.println("Euler's const, flout: =" + conflout);
thanks for the help