DevX Home    Today's Headlines   Articles Archive   Tip Bank   Forums   

Results 1 to 3 of 3
  1. #1
    Join Date
    Apr 2004
    Cape Town, SA

    Question Getting data from a web service from a java application

    Hi Experts.

    I have been working in Java for a while now, but have never had to interact with a web service. I have built a program using the JSDK that needs to query a web service. I'm not sure where to start with this .

    All i know is that I will be getting a URL that i must call and i must pass a number to this URL. I must then expect a XML document back.

    I'm maybe looking for someone to tell me more or less what to expect or do .

    1) How do I link to the web service from a Java application? Do i simply create a socket connection to the URL on port 80. Example http://www.dummywebservice.com?number=1000.

    2) Is there any other information (http header) that must be sent?

    3) Is the XML returned via the socket connection? Do i just read this in as if i was reading in a object over a socket?

    4) Are there any existing simple web services that follow i can use to query try and get this working? What are they and how do I query them?

    I'm really new to this and it kind of needs to be done quick. Any help would be really good. If possible demo code will help a lot.

    Please help me, Thanks.

    _/\/ \/\_

  2. #2
    Join Date
    Nov 2004

    I've posted this one many times....

    ..but noone has complained yet, so I guess it's working
    import java.net.*;
    import java.io.*;
     * Gets the contents of an url as a stringBuffer.
      Usage example:
    try {
      URL url=new URL("http://www.whatever.com/servlets/xyz?number=1000");
      SiteConn aConnection=new SiteConn(url);
      StringBuffer sb=aConnection.getContens();
    } catch (MalFormedURLException mfe) {
    class SiteConn {
      URL url = null;
      public SiteConn(URL url) {
        this.url = url;
      public StringBuffer getContents() throws Exception {
        StringBuffer buffer;
        String line;
        int responseCode;
        HttpURLConnection connection;
        InputStream input;
        BufferedReader dataInput;
        connection = (HttpURLConnection) url.openConnection();
        responseCode = connection.getResponseCode();
        if (responseCode != HttpURLConnection.HTTP_OK) {
          throw new Exception("HTTP response code: " +
        try {
          buffer = new StringBuffer();
          input = connection.getInputStream();
          dataInput = new BufferedReader(new InputStreamReader(input));
          while ( (line = dataInput.readLine()) != null) {
        catch (Exception ex) {
          return null;
        return buffer;
    Last edited by sjalle; 10-26-2005 at 05:48 AM. Reason: SORRY! I posted a lightweight version...
    eschew obfuscation

  3. #3
    Join Date
    Apr 2004
    Cape Town, SA
    Hi Sjalle.

    Very sorry you having to hear this one again. It is sort of what i thought, but the code really helps my understanding.
    Thanks a lot .

    _/\/ \/\_

Similar Threads

  1. Replies: 0
    Last Post: 06-21-2005, 11:01 AM
  2. Document-style Web Service Development in JAVA
    By V. Ramasamy in forum Java
    Replies: 0
    Last Post: 04-22-2003, 10:07 PM
  3. Replies: 0
    Last Post: 03-20-2003, 04:20 AM
  4. Replies: 0
    Last Post: 04-30-2001, 04:00 PM
  5. using Web Service classes
    By Tim Romano in forum .NET
    Replies: 6
    Last Post: 04-19-2001, 02:51 PM

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
HTML5 Development Center
Latest Articles
Questions? Contact us.
Web Development
Latest Tips
Open Source

   Development Centers

   -- Android Development Center
   -- Cloud Development Project Center
   -- HTML5 Development Center
   -- Windows Mobile Development Center

We have made updates to our Privacy Policy to reflect the implementation of the General Data Protection Regulation.