Very basic question !

[joe2280]

I'm new to Java...

Hi why those aren't true:

Example 1:
-------------------------------------------
StringBuffer sb = new StringBuffer("55555");
char c = 5;

if(sb.charAt(2) == c){
System.out.println("True");
}
-------------------------------------------

Example 2:
-------------------------------------------
StringBuffer sb = new StringBuffer("55555");
String s = "5";

if(sb.substring(1,2) == s){
System.out.println("True");
}
-------------------------------------------

Any suggestions ? Thank you.

[yawmark]

Example 1: 5 != '5'
Example 2: A String reference value and StringBuffer reference value will never be equal; they will never point to the same object in memory. Use the equals() method to compare object contents.

Change the following to make true...
Example 1:

char c = '5';

Example 2:

if (sb.substring(1, 2).equals(s))

[sjalle]

A String reference value and StringBuffer reference value will never be equal; they will never point to the same object in memory.

"Equality" in java is about content, not address. So a StringBuffer may
very well be equal to a String:

if (aStringBuffer.toString().equals(aString)) {
..
}