Calculsu 1 help
let y= f(x) be the function defined implicity by y^3+y+x = 0 and f(10) = -2
(a) find dy/dx at the point (10, -2).
(b) find the equation of the tangent line at (10, -2).
I got to the point were you solve for dy/dx but can't finsh
any help would be appreciated Thanks
dx/dy is the slope of the graph at that point. So you can solve Y = mX + b where Y is the y-coordinate (-2), X is the x-coordinate (10) m is the slope (dy/dx evaluated at 10, -2) for b. Then just use slope-intercept form: y = mx + b where y and x are variables.
Hope this helps.
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