Calculsu 1 help


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Thread: Calculsu 1 help

  1. #1
    Join Date
    Oct 2005
    Location
    Chicago
    Posts
    24

    Calculsu 1 help

    let y= f(x) be the function defined implicity by y^3+y+x = 0 and f(10) = -2
    (a) find dy/dx at the point (10, -2).
    (b) find the equation of the tangent line at (10, -2).

    I got to the point were you solve for dy/dx but can't finsh
    any help would be appreciated Thanks

  2. #2
    Join Date
    Aug 2003
    Posts
    313
    dx/dy is the slope of the graph at that point. So you can solve Y = mX + b where Y is the y-coordinate (-2), X is the x-coordinate (10) m is the slope (dy/dx evaluated at 10, -2) for b. Then just use slope-intercept form: y = mx + b where y and x are variables.

    Hope this helps.
    ~evlich

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