Calculsu 1 help

[Mcody2]

let y= f(x) be the function defined implicity by y^3+y+x = 0 and f(10) = -2
(a) find dy/dx at the point (10, -2).
(b) find the equation of the tangent line at (10, -2).

I got to the point were you solve for dy/dx but can't finsh
any help would be appreciated Thanks

[evlich]

dx/dy is the slope of the graph at that point. So you can solve Y = mX + b where Y is the y-coordinate (-2), X is the x-coordinate (10) m is the slope (dy/dx evaluated at 10, -2) for b. Then just use slope-intercept form: y = mx + b where y and x are variables.

Hope this helps.