Hi,

I have come across a problem which I'm unable to solve.

I'm creating a VB.Net application using Visual Studio 2005. On one of my forms, I've save a new record/row to my database. On this form, it also has a Open File Dialog component, which opens a picture, so that I can save the picture to the database. The problem occurs whenever I use the Open File Dialog, and open a picture, it comes up with the error saying it can't find my database. It shows me the path is it looking for it, and its the wrong path.

But when I don't use the Open File Dialog, it works perfectly fine. It saves the new record/row to the database. Its whenever I open a file using the Open File Dialog that it doesn't work.

If I hit the cancel button on the Open File Dialog it will still work, its whenever I open a file that it comes up with the error of not finding my database, as it is looking in the wrong directory.

I tried this in a new project and the same thing happens. It seems that whenever I open a file using the Open File Dialog, it is changing the path of where my database is, to the path of where the file I've just opened.

I have no idea why this is happening, please help me.

Here is my code for my database connection:

'Connection to the Access database
Public Const strConnection As String = _
Provider=Microsoft.Jet.OLEDB.4.0; " & _
"Data Source=./myDatabase.mdb;Persist Security Info=False"

and here is my code for my Open File Dialog:

OpenFileDialog.Filter = "Image files (.jpg, .jpeg, .bmp, .gif)|*.jpg;*.jpeg;*.bmp;*.gif"
If (OpenFileDialog.ShowDialog() = Windows.Forms.DialogResult.OK) Then
imageFileName = OpenFileDialog.FileName
txtImage.Text = imageFileName
End If

Thanks very much, any help much appreciated.