Random Number Generation with a Twist

[Hunterlmc]

Ok. This is not going to be the simplest thing to describe in a post. So, if I've confused anyone, please let me know. What I want to do is done in three steps.

Step One: I want to generate a random number to fall within a range between 0 and 100. I honestly think that this will be really easy. Now, this number will used to determine my game's start up options.

Step Two: I want to test that number on a sliding scale of 0 to 100. For example, when the program first launches all of the start up options will have an equal chance of being selected. So the initial scale will be:

0-20: Option 1
21-40: Option 2
41-60: Option 3
61-80: Option 4
81-100: Option 5

Step Three: Based on the initial option selection the above scale will change to something like the below (where option 1 was selected the first time out)

0-5: Option 1
6-10: Option 2
11-40: Option 3
41-50: Option 4
51-100: Option 5

What I'm hoping to get from people are thoughts/input on how this might be done.

Anyone? Any ideas?

L -

[Hunterlmc]

Here is how I'm generating the random number. Just in case people need to do the same thing.


// Create a byte array and the generator to hold the random value.
byte[] randomNumber = new byte[1];
RNGCryptoServiceProvider Gen = new RNGCryptoServiceProvider();

// Fill the array with a random value.
Gen.GetBytes(randomNumber);

// Convert the byte to an integer value to make the modulus operation easier.
int rand = Convert.ToInt32(randomNumber[0]);
return rand % 100 + 1;

[Phil Weber]

Why not simply use the System.Random class?

int num = new System.Random().Next(101);