Arrays and Structs

[gentlemanjim]

Hello,

I've written a simple program that allows a person to enter some personal information about a person or people. You enter the name, address and are prompted to enter the number of bank accounts for each person and the individual account numbers. However when I enter information for two people with one bank account each the second person's account number comes out as garbage. Does anyone have any helpful suggestions??



#include <iostream>
using namespace std;

struct account{
int accountnum;
char accType;
float balance;
};
typedef struct account A;

struct Customer{
string name;
string address;
A * accArray;
};

typedef struct Customer Cu;

int main(){

int numCust, numAccounts;

cout << "Enter number of customers"<<endl;
cin >>numCust;
cin.ignore();

Cu * cArray = new Cu[numCust];

for ( int i=0; i < numCust; i++)
{
cout << "Enter name"<<endl;
getline(cin, cArray[i].name);
cout <<"Enter address"<<endl;
getline(cin, cArray[i].address);
cout <<"Enter number of accounts"<<endl;
cin >> numAccounts;
cArray[i].accArray = new A[numAccounts];

for ( int j=0; j < numAccounts; j++)
{
cout <<"enter account number for "<< j+1<<endl;
cin >> cArray[i].accArray[j].accountnum;
}
cin.ignore();
}
cout << "\nName \t\t Address\t Account Number"<<endl;

for (int i=0; i< numCust; i++)
{
cout <<cArray[i].name<<"\t\t"<<cArray[i].address<<"\t"<<cArray[i].accArray[i].accountnum<<endl;
}
system ("Pause");
return 0;

}

[jonnin]

Its your print loop.
for i = 0....
second time through, your print account[1] (the valid one is account[0]) because you indexed everything off i but accounts needs a second index just like you had when you put them in.

[Peter_APIIT]

You declare a variable i in for loop scope and use it in another for loop score. Wrong.

[Danny]

You declare a variable i in for loop scope and use it in another for loop score. Wrong.

Each for loop has its own scope, so the variable i declared in one loop doesn't conflict with another i declared in the second loop.