Problem regarding javax.servletpackage

[stanley]

I am getting problem in regards to the package javax.servlet.*
not found although I have set the correct path in my autoexec.bat file
the path for servlet is as follows:
set path=c:\jsdk2.0\bin;
set classpath=c:\jsdk2.0\lib;
which is in my root directory
So I created another director javadir and I was compiling this
servlet programme. It threw me this exception
Please help.

[Paul Clapham]

The servlet classes come in a jar file (or maybe more than one). Did you
add it (or them) to your classpath? Doesn't look like it.

PC2

stanley <stancher56@hotmail.com> wrote in message
news:3a07a896$1@news.devx.com...
>
> I am getting problem in regards to the package javax.servlet.*
> not found although I have set the correct path in my autoexec.bat file
> the path for servlet is as follows:
> set path=c:\jsdk2.0\bin;
> set classpath=c:\jsdk2.0\lib;
> which is in my root directory
> So I created another director javadir and I was compiling this
> servlet programme. It threw me this exception
> Please help.
>

[Patel]

Since JSDK 2 you need to set your class path to c:\jsdk2.0\lib\"somejarfile".jar.
Point your class path to the jar file that has javax package in it.

"stanley" <stancher56@hotmail.com> wrote:
>
>I am getting problem in regards to the package javax.servlet.*
>not found although I have set the correct path in my autoexec.bat file
>the path for servlet is as follows:
>set path=c:\jsdk2.0\bin;
>set classpath=c:\jsdk2.0\lib;
>which is in my root directory
> So I created another director javadir and I was compiling this
> servlet programme. It threw me this exception
> Please help.
>

[prasad]

hi,
I think u should compile the file giving
the classpath attribute along with the file
name

like

javac -classpath <ClasspathOfJarFile> <filename>

love PRASAD