Challanging Question----How do i represent a matrix schema.

[manish jain]

Can anybody suggest me that how do i represent a generic matrix schema.

For now consider it as 2x2 matrix.

c1 c2
r1 100 200
r2 300 400

Data is 100,200,300,400.

it will be better if u can suggest upto any level.ie NxN matrix.

Thanks in Advance
Manish.

[Rohit Wason]

Hi Manish
Long time for me to be out of touch from the forum Guys!
Not much complex man:
Two ways:
1)
<rows>
<row>
<col>100</col>
<col>150</col>
<col>300</col>
..............
</row>

<row>
<col>150</col>
<col>250</col>
<col>230</col>
..............
</row>
.......
</rows>
This way has got the simplicity of having data in a free form - as-it-comes
basis, but drawback of indexing and addressing - you can't access the M[n,m]th
element.

2)
<cells>
<cell row="1" col="1">120</cell>
<cell row="1" col="2">220</cell>
<cell row="1" col="3">300</cell>
<cell row="2" col="1">250</cell>
<cell row="2" col="2">520</cell>
<cell row="2" col="3">100</cell>
<cell row="3" col="1">105</cell>
...
...
..
</cells>
This has the drawback of storage time (somewhat), but a good addressing and
indexing capabilities.

You can have n-number of solutions to it, but don't call them challanging

Rohit

[Eric]

Hey Rohit,

I am VERY new to XML, so what I'm about to suggest may be way off, but
I thought I'd throw something out there for consideration.

Given the solution you've proposed in your point (2), could that be improved
upon to represent N-dimensional matrices by replacing the "row" and "col"
attributes of your <cell> element with this:

<!ATTLIST cell index NMTOKENS> ??

(I don't have my XML reference at hand...is that syntax correct? I mean an
attribute to the cell element named "index" that holds one or more NMTOKEN
items.)

You could then represent an N-dimensional matrix using cell elements such
as:

<matrix name="demo">
<cell index="3 7 1 1">...</cell>

[Steve]

Rohit:
Method one works well for me. You could address the
individual elements using the element Indexes of a node list
ie:

set RowIndex = XMLDoc.SelectNodes("//rows[x]")
Set ColIndex = RowIndex.SelectNodes("//col[y]")

Then changing the values of x and y to address the
M(x,y)th element. Not as simple as iterating through
a recordset, but still allowing you to directly access
any given component.

Steve


"Rohit Wason" <rohitw@futuresoftindia.com> wrote:
>
>Hi Manish
>Long time for me to be out of touch from the forum Guys!
>Not much complex man:
>Two ways:
>1)
><rows>
> <row>
> <col>100</col>
> <col>150</col>
> <col>300</col>
> ..............
> </row>
>
> <row>
> <col>150</col>
> <col>250</col>
> <col>230</col>
> ..............
> </row>
> .......
></rows>
>This way has got the simplicity of having data in a free form - as-it-comes
>basis, but drawback of indexing and addressing - you can't access the M[n,m]th
>element.
>
>2)
><cells>
><cell row="1" col="1">120</cell>
><cell row="1" col="2">220</cell>
><cell row="1" col="3">300</cell>
><cell row="2" col="1">250</cell>
><cell row="2" col="2">520</cell>
><cell row="2" col="3">100</cell>
><cell row="3" col="1">105</cell>
>...
>...
>..
></cells>
>This has the drawback of storage time (somewhat), but a good addressing
and
>indexing capabilities.
>
>You can have n-number of solutions to it, but don't call them challanging
>
>Rohit
>