basic question need help!

[j.d.]

Ok, so I need to know how to figure out a certain number using a very simple
while loop. All we know is that when a person carries 2 objects at a time,
there is 1 leftover (also known as number % 2 = 1) ... the same goes for
when the person carries 3,4,5, or 6 at a time. If they carry them 7 at a
time then there are none leftover (number % 7 = 0). All I've been told is
that the number is over 300 and to use a while loop and very basic commands.
Thanks in advance for the help.

Try this,

public class DoIt {
public static void main(String[] args) {
System.out.println("Do your own homework!");
}
}

"j.d." <jdn@neo.tamu.edu> wrote:
>
>Ok, so I need to know how to figure out a certain number using a very simple
>while loop. All we know is that when a person carries 2 objects at a time,
>there is 1 leftover (also known as number % 2 = 1) ... the same goes for
>when the person carries 3,4,5, or 6 at a time. If they carry them 7 at
a
>time then there are none leftover (number % 7 = 0). All I've been told
is
>that the number is over 300 and to use a while loop and very basic commands.
> Thanks in advance for the help.

[j.d.]

hey,i got it figured out now, but thanks for your help... ****....

<java.@127.0.0.1> wrote:
>
>Try this,
>
>public class DoIt {
> public static void main(String[] args) {
> System.out.println("Do your own homework!");
> }
>}
>
>"j.d." <jdn@neo.tamu.edu> wrote:
>>
>>Ok, so I need to know how to figure out a certain number using a very simple
>>while loop. All we know is that when a person carries 2 objects at a time,
>>there is 1 leftover (also known as number % 2 = 1) ... the same goes for
>>when the person carries 3,4,5, or 6 at a time. If they carry them 7 at
>a
>>time then there are none leftover (number % 7 = 0). All I've been told
>is
>>that the number is over 300 and to use a while loop and very basic commands.
>> Thanks in advance for the help.
>

[Brad O'Hearne]

Remember everyone, let's keep the gloves on! Also, especially if you are
going to take issue to a post, please have the courage to include a
legitimate email address at which you can be contacted (127.0.0.1 won't work
for a domain name). j.d. asked a legitimate question. j.d., if you still
need help, let the group know.

Thanks!

BradO
--
Brad O'Hearne
DevX Section Leader

<java.@127.0.0.1> wrote in message news:3d979501$1@10.1.10.29...
>
> Try this,
>
> public class DoIt {
> public static void main(String[] args) {
> System.out.println("Do your own homework!");
> }
> }
>
> "j.d." <jdn@neo.tamu.edu> wrote:
> >
> >Ok, so I need to know how to figure out a certain number using a very
simple
> >while loop. All we know is that when a person carries 2 objects at a
time,
> >there is 1 leftover (also known as number % 2 = 1) ... the same goes for
> >when the person carries 3,4,5, or 6 at a time. If they carry them 7 at
> a
> >time then there are none leftover (number % 7 = 0). All I've been told
> is
> >that the number is over 300 and to use a while loop and very basic
commands.
> > Thanks in advance for the help.
>

[j.d.]

I have figured out the problem. I know not everyone on here is like that,
but it was still a bit upsetting to someone just trying to learn.

Thanks,

J.D.

"Brad O'Hearne" <brado@neurofire.com> wrote:
>Remember everyone, let's keep the gloves on! Also, especially if you are
>going to take issue to a post, please have the courage to include a
>legitimate email address at which you can be contacted (127.0.0.1 won't
work
>for a domain name). j.d. asked a legitimate question. j.d., if you still
>need help, let the group know.
>
>Thanks!
>
>BradO
>--
>Brad O'Hearne
>DevX Section Leader
>
><java.@127.0.0.1> wrote in message news:3d979501$1@10.1.10.29...
>>
>> Try this,
>>
>> public class DoIt {
>> public static void main(String[] args) {
>> System.out.println("Do your own homework!");
>> }
>> }
>>
>> "j.d." <jdn@neo.tamu.edu> wrote:
>> >
>> >Ok, so I need to know how to figure out a certain number using a very
>simple
>> >while loop. All we know is that when a person carries 2 objects at a
>time,
>> >there is 1 leftover (also known as number % 2 = 1) ... the same goes
for
>> >when the person carries 3,4,5, or 6 at a time. If they carry them 7
at
>> a
>> >time then there are none leftover (number % 7 = 0). All I've been told
>> is
>> >that the number is over 300 and to use a while loop and very basic
>commands.
>> > Thanks in advance for the help.
>>
>
>