There is an error in my code thus far, which has managed to escape me, so I pose it to you guys. It is supposed to take a long number and count how many of the same there are. What happens though is you need to eneter 1+ the numbers. Ex. 3892478 it would print out the any numbers to 6. So for all 9 to be accounted for, one would need to put in 10 numbers.
public class Parser3 {

public static void main(String [] args) {

//declare variables
int [] frequencyArray = new int [10];
String userInput;
String [] numbers = {"Zero", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"};

// ask user for input
System.out.print("Please input your student number: ");
userInput= MyInput.readString();

//Take the user input and count the number of occurences and put the occurences into an array
for(int i = 0; i < userInput.length(); i ++) {
if (userInput.charAt(i) == '0') {
frequencyArray[0] ++;
continue;
} else if (userInput.charAt(i) == '1') {
frequencyArray[1] ++;
continue;
} else if (userInput.charAt(i) == '2') {
frequencyArray[2] ++;
continue;
} else if (userInput.charAt(i) == '3') {
frequencyArray[3] ++;
continue;
} else if (userInput.charAt(i) == '4') {
frequencyArray[4] ++;
continue;
} else if (userInput.charAt(i) == '5') {
frequencyArray[5] ++;
continue;
} else if (userInput.charAt(i) == '6') {
frequencyArray[6] ++;
continue;
} else if (userInput.charAt(i) == '7') {
frequencyArray[7] ++;
continue;
} else if (userInput.charAt(i) == '8') {
frequencyArray[8] ++;
continue;
} else if (userInput.charAt(i) == '9') {
frequencyArray[9] ++;
continue;
}//end if statements
}//end for

System.out.println("In the number " + userInput + " there are: ");

//Print out the values in the array with the appropriate ending
for(int j = 0; j <userInput.length(); j ++) {
if (frequencyArray[j] > 0) {
System.out.println(frequencyArray[j] + " " + numbers[j] + "(s)");
}//end if
}//end for

// Print the highest value in the array

//Print out the word equivalent of the numbers

}//end main

I can also use suggestions on how to find the value that is enetered most often, and how to print out the word equivalent (ex. 37263 = Three, Seven, Two, Six, Three)