throw exceptions

[tyris]

hi all,
i'm new to java language and i'd like to know :
i have made a progam where i throw java.lang.NullPointerException this way
:


public StringBuffer search(String SQLstring, StringBuffer sb_DATA) throws
java.lang.NullPointerException {
try
{
.....
}
catch (NullPointerException d)
{
System.out.println("error : " + d + "\n");
d.printStackTrace();
}
}

the problem is that when a NullPointerException exist, i do have this result
:

error : java.lang.NullPointerException

and nothing else (i mean i don't know where in my code is the error)


is there a way to know which code part is the reason of the error ?
Best regards ,
Elise

[Rajkamal Gopinath]

Hi

1) remove throws NullPointerException in the first line, because its not
needed when you handle it by using try and catch.

2) Remove d.printStackTrace() from your code , since you need to know in
which line you have the error, rather than which method in the whole application
which caused the error

3) Insert System.println() in every line with some different messages and
execute it...

you will find the error easily

Regards

Rajkamal


"tyris" <kea@mailcity.com> wrote:
>
>hi all,
>i'm new to java language and i'd like to know :
>i have made a progam where i throw java.lang.NullPointerException this way
>:
>
>
>public StringBuffer search(String SQLstring, StringBuffer sb_DATA) throws
>java.lang.NullPointerException {
>try
> {
>.....
> }
>catch (NullPointerException d)
> {
> System.out.println("error : " + d + "\n");
> }
>}
>
>the problem is that when a NullPointerException exist, i do have this result
>:
>
>error : java.lang.NullPointerException
>
>and nothing else (i mean i don't know where in my code is the error)
>
>
>is there a way to know which code part is the reason of the error ?
>Best regards ,
>Elise
>