Username and Password validation, plus switchcase

[Annu Sharma]

I'm currently struggling with a problem. I have to make a program where I
accept both username and password and if they are correct, the screen should
then give 4 options:
1. Item
2. Quantity
3. User Details
4. Exit

For this I know that you have to use switch case (for more than one condition).
I also have to use the "do...while loop". I have written the following
and if you can please correct me where I'm going wrong.....I'm honestly getting
very lost!!

#include<iostream.h>
#include<string.h>
void item();
void quantity();
void UserDetails();
void exit();
void main()
{
char str1[12];
char str2[12];
int Result;
int Result2;
char reply;
int choice;
do
{
cout<<"Enter username\n";
cin>>str1;
Result=strcmp(str1, "Joe");
cout<<"Enter password\n";
cin>>str2;
Result2=strcmp(str2, "Bloggs");
if(Result==0 && Result2==0)
cout<<"Username and Password are valid\n";
cout<<"1. ITEM\n";
cout<<"2. QUANTITY\n";
cout<<"3. USER DETAILS\n";
cout<<"4. EXIT\n";
cout<<"Please enter the choice (1,2,3,4)\n";
cin>>choice;
switch(choice)
{
case 1:
{
item();
break;
}
case 2:
{
quantity();
break;
}
case 3:
{
UserDetails();
break;
}
case 4:
{
exit();
break;
}
}
void item()
{
int a,b,c;
char name[12];
cout<<"Enter item name\n";
cin>>name;
cout<<Enter item price\n";
cin>>a;
cout<<"Enter number of items\n";
cin>>b;
c=a*b;
cout<<"Total price of items is: "<<c;
}
void quantity()
{
int a,b,c;
char name[12];
cout<<"Enter item name\n";
cin>>name;
cout<<"Enter quantity on hand\n";
cin>>a;
cout<<"Enter quantity ordered\n";
cin>>b;
c=a-b;
cout<<"The quantity value is: "<<c;
}
void UserDetails()
{
char name[12];
char address[30];
char phone[9];
int purchase;
cout<<"Enter name\n";
cin>>name;
cout<<"Enter address\n";
cin>>address;
cout<<"Enter phone number\n";
cin>>phone;
cout<<"Enter number of items purchased\n";
cin>>purchase;
}
else
{
cout<<"Username and Password are invalid\n";
}
cout<<"Do you want to continue (y/n)?\n";
cin>>reply;
}while(reply=='y');
}


I get one error message "Declaration syntax error" but I can't think of how
to resolve this. I would really appreciate it if you could help me solve
it.

[vector]

Annu,

You need to remove the semicolon after the last statement unless your doing
something else which I cannot think of that would cause you to have a semicolon
after I while loop.


>}while(reply=='y');<-------------remove semicolon,
then recompile

Try it,:)


Vector

[Jim Annunziato]

Annu-- you have a few errors in your program, I rewrote it enough so that
it will compile and run. There is still quite a bit you can do to the program
to format it the way you would like. I tried to put comments where I found
errors; here is the source code so you can compare it with yours. Also it
is easier to read the code you write if you indent. Hope this helps you.


#include<iostream.h>
#include <stdlib.h>
#include<string.h>


void item();
void quantity();
void UserDetails();

//void exit(); you can use the built in function exit in the
// stdlib.h file"



void main()
{


char str1[12];
char str2[12];
int Result;//normally a variable is all lower case unless it is
//a constant.

int Result2;

//char reply; reply is not used anywhere in your program. you can
// delete this line

int choice;


do
{
cout<<"Enter username\n";
cin>>str1;
Result=strcmp(str1, "Joe");
cout<<"Enter password\n";
cin>>str2;
Result2=strcmp(str2, "Bloggs");
}while ((Result !=0)&& (Result2 !=0));// you need to have a
//while statement with
// a do. do...while.



//if(Result==0 && Result2==0) you do not need this if line now.

cout<<"Username and Password are valid\n";
cout<<"1. ITEM\n";
cout<<"2. QUANTITY\n";
cout<<"3. USER DETAILS\n";
cout<<"4. EXIT\n";
cout<<"Please enter the choice (1,2,3,4)\n";
cin>>choice;

switch(choice)
{
case 1: item();
break;

case 2: quantity();
break;

case 3: UserDetails();
break;

case 4: exit(0);

}


}




void item()
{
int a,b,c;
char name[12];

cout<<"Enter item name\n";
cin>>name; //you declared the char array "name", but you
// didn't use it anywhere in the function.

cout<<"Enter item price\n";
cin>>a;
cout<<"Enter number of items\n";
cin>>b;
c=a*b;
cout<<"Total price of "<<name<<" is: "<<c;
// I inserted name down here.
}


void quantity()
{
int a,b,c;
char name[12];

cout<<"Enter item name\n";
cin>>name; // same as above variable declared but not
// used

cout<<"Enter quantity on hand\n";
cin>>a;
cout<<"Enter quantity ordered\n";
cin>>b;
c=a-b;
cout<<"The quantity of " <<name <<" is: "<<c;
// added name here again
}


void UserDetails()
{
char name[12];
char address[30];
char phone[9];
int purchase;

cout<<"Enter name\n";
cin>>name;
cout<<"Enter address\n";
cin>>address;
cout<<"Enter phone number\n";
cin>>phone;
cout<<"Enter number of items purchased\n";
cin>>purchase;
// this data is is brought in, but is not used anywhere
// in the program.
}















"Annu Sharma" <una_00@yahoo.com> wrote:
>
>I'm currently struggling with a problem. I have to make a program where
I
>accept both username and password and if they are correct, the screen should
>then give 4 options:
>1. Item
>2. Quantity
>3. User Details
>4. Exit
>
>For this I know that you have to use switch case (for more than one condition).
> I also have to use the "do...while loop". I have written the following
>and if you can please correct me where I'm going wrong.....I'm honestly
getting
>very lost!!
>
>#include<iostream.h>
>#include<string.h>
>void item();
>void quantity();
>void UserDetails();
>void exit();
>void main()
>{
>char str1[12];
>char str2[12];
>int Result;
>int Result2;
>char reply;
>int choice;
>do
>{
>cout<<"Enter username\n";
>cin>>str1;
>Result=strcmp(str1, "Joe");
>cout<<"Enter password\n";
>cin>>str2;
>Result2=strcmp(str2, "Bloggs");
>if(Result==0 && Result2==0)
>cout<<"Username and Password are valid\n";
>cout<<"1. ITEM\n";
>cout<<"2. QUANTITY\n";
>cout<<"3. USER DETAILS\n";
>cout<<"4. EXIT\n";
>cout<<"Please enter the choice (1,2,3,4)\n";
>cin>>choice;
>switch(choice)
>{
>case 1:
> {
> item();
> break;
> }
>case 2:
> {
>quantity();
>break;
>}
>case 3:
>{
>UserDetails();
>break;
>}
>case 4:
>{
>exit();
>break;
>}
> }
>void item()
>{
>int a,b,c;
>char name[12];
>cout<<"Enter item name\n";
>cin>>name;
>cout<<Enter item price\n";
>cin>>a;
>cout<<"Enter number of items\n";
>cin>>b;
>c=a*b;
>cout<<"Total price of items is: "<<c;
>}
>void quantity()
>{
>int a,b,c;
>char name[12];
>cout<<"Enter item name\n";
>cin>>name;
>cout<<"Enter quantity on hand\n";
>cin>>a;
>cout<<"Enter quantity ordered\n";
>cin>>b;
>c=a-b;
>cout<<"The quantity value is: "<<c;
>}
>void UserDetails()
>{
>char name[12];
>char address[30];
>char phone[9];
>int purchase;
>cout<<"Enter name\n";
>cin>>name;
>cout<<"Enter address\n";
>cin>>address;
>cout<<"Enter phone number\n";
>cin>>phone;
>cout<<"Enter number of items purchased\n";
>cin>>purchase;
>}
>else
>{
>cout<<"Username and Password are invalid\n";
>}
>cout<<"Do you want to continue (y/n)?\n";
>cin>>reply;
>}while(reply=='y');
>}
>
>
>I get one error message "Declaration syntax error" but I can't think of
how
>to resolve this. I would really appreciate it if you could help me solve
>it.
>
>