Array sorting

[Garu]

This is long winded but..
# include<iostream>
using std::cout;
using std::endl;
# include<iomanip>
using std::setw;
#include <cstdlib>
#include <ctime>
int main()
{
const int arraysize = 100;
srand (time(0));

for (int i = 1; i <=15; i++){
cout << setw(10) << 1 + rand() % 100 << endl;
if (i% 99 == 0)
cout << endl;
}
return 0;
}

This program is to create a function the uses the random number generator
to populate a 5X3 array with random numbers in the range of 1 to 100, and
display array in 5 rows by 3 columns
My question(s): How to I display as 5X3 array using setw etc..

How do you populate an 100 number array, and work it into the if statement?
Do I have to use int n[array size] = {1,2,3...and write all 100 numbers,
or is their a shorter method?
Am I even close with what I got?

[jonnin]

You are close. If the loop counter+1 % columns == 0 then write end of line.
here, if you assume filled array with loop counter from 0, we get
0 1 2
3 4 5
6 7 8
9 10 11
12 13 14

watch out for 0, 0 % anything == 0 ...

fill each element with a number in a loop.

for(x = 0 ... 99)
array[x] = (x or rand() or whatever)





"Garu" <gchambers12@home.ca> wrote:
>
>This is long winded but..
># include<iostream>
>using std::cout;
>using std::endl;
># include<iomanip>
>using std::setw;
>#include <cstdlib>
>#include <ctime>
>int main()
>{
> const int arraysize = 100;
>srand (time(0));
>
>for (int i = 1; i <=15; i++){
> cout << setw(10) << 1 + rand() % 100 << endl;
> if (i% 99 == 0)
> cout << endl;
>}
>return 0;
>}
>
>This program is to create a function the uses the random number generator
>to populate a 5X3 array with random numbers in the range of 1 to 100, and
>display array in 5 rows by 3 columns
> My question(s): How to I display as 5X3 array using setw etc..
>
> How do you populate an 100 number array, and work it into the if statement?
> Do I have to use int n[array size] = {1,2,3...and write all 100 numbers,
>or is their a shorter method?
> Am I even close with what I got?
>
>
>
>
>