overloading a virtual function

[Asa]

Hi,
is it possible to overload a virtual function like the following:

I have an abstract base class, let's call it BaseProtocol. BaseProtocol has
a virtual function, called receive(type_a ...)

I have two classes that inherit from BaseProtocol, we can call them Protocol1
and Protocol2.

What I want is the following:

Protocol1 should implement the virtual function with type_a, receive(type_a)


and

Protocol2 should implement the virtual function with a type_b,
receive(type_b)

Is this possible to do by overloading the virtual receive() in the base class???
It would be great if someone knows anything about this.

Thanx/Asa

[Danny Kalev]

Asa,
In general, you can override a virtual function only if the signatures
of the base and derived versions match. In your example, the signatures
don't match so what you're actually getting is a function that hides the
base class's virtual. Why don't you define two virtuals in the base
class? Alternatively, you can hide the actual parameter's type in a
uniform class or struct (or even void*, not my favorite way of using C++
but sometimes it's inevitable).

Danny

Asa wrote:
>
> Hi,
> is it possible to overload a virtual function like the following:
>
> I have an abstract base class, let's call it BaseProtocol. BaseProtocol has
> a virtual function, called receive(type_a ...)
>
> I have two classes that inherit from BaseProtocol, we can call them Protocol1
> and Protocol2.
>
> What I want is the following:
>
> Protocol1 should implement the virtual function with type_a, receive(type_a)
>
> and
>
> Protocol2 should implement the virtual function with a type_b,
> receive(type_b)
>
> Is this possible to do by overloading the virtual receive() in the base class???
> It would be great if someone knows anything about this.
>
> Thanx/Asa