storing more than one word in char arrays

[h2ombre]

How can you store more than one word in a char array?

[Danny Kalev]

how about:

char arr[] = "hello world";

Danny

h2ombre wrote:
>
> How can you store more than one word in a char array?

[rmcc]

"h2ombre" <bwbrown@ukans.edu> wrote:
>
>How can you store more than one word in a char array?
If the char array is big enough, use strcat from string lib functions.


#include <string.h>
#include <stdio.h>

void main( void )
{
char string[80];
strcpy( string, "Hello world from " );
strcat( string, "strcpy " );
strcat( string, "and " );
strcat( string, "strcat!" );
printf( "String = %s\n", string );
}

"h2ombre" <bwbrown@ukans.edu> wrote:
>
To do this you must use the cin.getline() function. for example if you wish
to hold "John Doe" in Name[30]; you must say
cout << "Please enter your name : ";
cin.getline(){Name,30,'\n');
note that '\n' will be the default character. good luck

*Traveling the world!!
>How can you store more than one word in a char array?

[Richard Vickers]

"h2ombre" <bwbrown@ukans.edu> wrote:
>
>How can you store more than one word in a char array?

Use a second EOS indicator (say @) and check each string.
Store "Easy@Fix" in the char array....upon retrieval, check
the string for the @...characters before are first array,
characters after are second array. @ in first position
indicates Empty first string. @ in last position indicates
Empty second string. String length 1 AND @ in first position,
both strings Empty. Just a thought while reading.

Richard Vickers
rvicke@earthlink.net

[jan]

"h2ombre" <bwbrown@ukans.edu> wrote:
>
>How can you store more than one word in a char array?

The responses so far are all correct if you are storing words and not phrases,
which is the more general problem. The classic solutions to this problem
take the form of using the null character between phrases and a double null
character at the end to signal the end of the set of phrases. So, the following
is a set of phrases. \0 is the null character.

char *pStr = "Phrase 1 - has all sorts of !@#$# characters\0Phrase 2: another
one\0\0";

Parsing this is frightfully easy. Just use the pointer as is for the entire
first string, then increment the pointer by the length of the string plus
the null, then use it again until the pointer points to a null.

while (pStr)
{
printf("Phrase: %s\n", pStr);
pStr += strlen(pStr) + 1;
}