Why does my program run with strange order?

[gnosnahz]

Could somebody please suggest me at what situation a progarm could run with the order that is not as it looks like.

eg: When the code should run sequencely, it does not.

In my case, I don't have many threads: I have a GUI and a main. The program will begin to run until it gets the GUI interface and then it stops to wait for me to press one button to continue. A lot of strange problems come out after that. This is one of it.

I am not sure where my problem resides, but it starts to be strange near something like the following (when it prints something. )


public void waitToStart(PrintWriter pW)throws IOException
{
while(!start){}
startRun(pW);
}
public void startRun(PrintWriter pW)throws IOException
{
while(!finished)
{
.
.
.
System.out.println("******");
pW.println("******");
pW.flush();
.
.
.
}
}


Any suggestions please. Thanks very much.

[sjalle]

If you have no threads then this looks strange indeed. I would have done the following
changes:
The waitToStart method should be invoked by an eventhandler (the buttons
actionPerformed ?) or invoked at end of GUI initiation, loose the while(!start)
{} "thing", set finished=false, and finally create & start a normal priority
thread that perform the while(!finished) -loop. You would probably (?) also
need a button with an eventhandler that sets finished=true if this flag isn't
set (safely) within the while(!finished) -loop.

[gnosnahz]

Thanks a lot sjalle. It is solved.

Only to call the waitToStart method in an eventhandler is enough to me so far.

But why I can not do it the way I did it before?

Thanks.

[sjalle]

Well, a tight loop like while(!start) {}, when start initially = false,
doesn't allow much other things to happend, like setting start=true....