Strings & Arrays

[Gunsmith2112]

I am trying to write a program that Store 5 numbers these values into an array of int []. Using the length of the array in a for() loop and decrementing the loop counter, write the array values in reverse order to the screen. Thats the easy part This is were i am having issues add code to read 5 words from the Console (user input). Store these values into an array of string []. Make sure the string[] array is large enough to hold at least 6 values. Store the string constant “end_of_array” into the last element of the array. Using a do…while() loop, print out the 1st and 3rd letters of each word (two letters per line) using the substring function. Can someone please help out.

#include <iostream>
#include <string>

using namespace std;


const char* END_OF_ARRAY = "end_of_array";

int main()
{
string theArray[6];
theArray[5] = END_OF_ARRAY;
cout << "Please enter 5 strings of your choice\n";
for(int counter = 0; counter < 5; counter++)
{
cin >> theArray[counter];
}

cout << "\nThe strings are:\n";
int counter = 0;
do
{
cout << theArray[counter++] << " \n";
} while (theArray[counter] != END_OF_ARRAY);

cin.get();
return 0;
}

[vijayan]

for(int counter = 0; counter < 5; counter++)
{
    cin >> theArray[counter];
}

this will not work correctly if the string that the user enters contains white spaces. to accept a complete line of input (up to the newline), use std::getline

for( std::size_t counter = 0; counter < 5; counter++ )
{
    std::getline( std::cin, theArray[counter] ) ;
}

> print out the 1st and 3rd letters of each word (two letters per line) using the substring function.

using the substring function? this is really asinine.
to access characters at specific positions in a string, use the array subscript [] operator.

std::size_t counter = 0 ;
do
{
   // assuming that the 'first' letter is at postion 0
  if( theArray[counter].size() >= 3 )
     std::cout << theArray[counter][0] << theArray[counter][2]  << '\n' ;
  else
    std::cout << "the string has less than three characters\n" ;
  
  ++counter ;

} while( counter < 5 ) ;

while( theArray[counter] != END_OF_ARRAY ) ;
has a problem if the user is unkind enough to enter "END_OF_ARRAY" as one of the five strings.

[Gunsmith2112]

I get compiling Errors

arrays.cpp(31) : error C2143: syntax error : missing ';' before '!='
arrays.cpp(31) : error C2059: syntax error : ')'

[vijayan]

post the code for which you are getting the errors.

[Gunsmith2112]

It comiples thank you for all your help


#include <iostream>
#include <string>
using namespace std;

// Line 15 user inputs 5 words
// Line 18 int set to 0 and will count 1 until it hits 5 Arrays
// Line 28 the first [0] is the string 2nd [2] is how many letters it is going to count
// Line 24-32 Running the do while loop that has to access the Array Boxes
// Line 34 End_of_Array when the expression is true
const char* END_OF_ARRAY = "end_of_array";

int main()
{
string theArray[6];
theArray[5] = END_OF_ARRAY;
cout << "Please enter 5 strings of your choice\n";
for (int counter=0;counter < 5;counter++)
{
cin >> theArray[counter];
}

cout << "\nThe strings are:\n";
int counter = 0 ;
do
{

if( theArray[counter].size() >= 3 )
cout << theArray[counter][0] << theArray[counter][2] << "\n" ;
else
cout << "the string has less than three characters\n" ;

++counter ;

} while( counter < 5 );

cin.get();
return 0;
}

[vijayan]

> // Line 28 the first [0] is the string 2nd [2] is how many letters it is going to count

oh, no!. i presume that this is the line you are referring to:

cout << theArray[counter][0] << theArray[counter][2] << "\n" ;

here, theArray[counter] is the string (at position counter in the array)
theArray[counter][0] is the first char in that string (at position 0).
and theArray[counter][2] is the third char in that string (at position 2).

and to send a single char to a stream, use << '\n' (instead of << "\n"). it is more efficient.