XSL and XML problem

[Svenne]

lets say I have the following XML database design:

<root>
<test>
<name>monkey</name>
<test2>a</test2>
<test2>a</test2>
<test2>a</test2>
<test2>a</test2>
</test>
<test>
<name>eel</name>
<test2>a</test2>
<test2>a</test2>
</test>
</root>

how would I do in XSL to output all test2 tags no matter how many there are?

should this design be better?

<root>
<test>
<name>monkey</name>
<test2>
<test3>a</test3>
<test3>a</test3>
<test3>a</test3>
</test2>

</test>
<test>
<name>monkey</name>
<test2>
<test3>a</test3>
<test3>a</test3>
<test3>a</test3>
<test3>a</test3>
<test3>a</test3>
</test2>

</test>
</root>

how should I do to output all test 3 tags? no matter how many they are?

I have tried to put one for-each loop in another for-each loop but that only
outputs one of the test3 tags, not all of them

<xsl:for-each select="root/test">
<xsl:value-of select="name"/>
<xsl:for-each select="root/test2">
<xsl:value-of select="test3"/>
</xsl:for-each>
</xsl:for-each>

I'd appreciate an answer
thanks alot!

[AC]

What about using <xsl:for-each select="//test2"> or <xsl:for-each select="//test3">?

AC

"Svenne" <matrx@home.se> wrote:
>
>lets say I have the following XML database design:
>
><root>
> <test>
> <name>monkey</name>
> <test2>a</test2>
> <test2>a</test2>
> <test2>a</test2>
> <test2>a</test2>
> </test>
> <test>
> <name>eel</name>
> <test2>a</test2>
> <test2>a</test2>
> </test>
></root>
>
>how would I do in XSL to output all test2 tags no matter how many there
are?
>
>should this design be better?
>
><root>
> <test>
> <name>monkey</name>
> <test2>
> <test3>a</test3>
> <test3>a</test3>
> <test3>a</test3>
> </test2>
>
> </test>
> <test>
> <name>monkey</name>
> <test2>
> <test3>a</test3>
> <test3>a</test3>
> <test3>a</test3>
> <test3>a</test3>
> <test3>a</test3>
> </test2>
>
> </test>
></root>
>
>how should I do to output all test 3 tags? no matter how many they are?
>
>I have tried to put one for-each loop in another for-each loop but that
only
>outputs one of the test3 tags, not all of them
>
><xsl:for-each select="root/test">
> <xsl:value-of select="name"/>
> <xsl:for-each select="root/test2">
> <xsl:value-of select="test3"/>
> </xsl:for-each>
></xsl:for-each>
>
>I'd appreciate an answer
>thanks alot!

[Jack]

Try the following.
<xsl:template match="test">
<xsl:apply-templates select="test2" />
</xsl:template>
<xsl:template match="test2">
<xsl:value-of select="."/>
</xsl:template>


"AC" <ac7117@eudoramail.com> wrote:
>
>What about using <xsl:for-each select="//test2"> or <xsl:for-each select="//test3">?
>
>AC
>
>"Svenne" <matrx@home.se> wrote:
>>
>>lets say I have the following XML database design:
>>
>><root>
>> <test>
>> <name>monkey</name>
>> <test2>a</test2>
>> <test2>a</test2>
>> <test2>a</test2>
>> <test2>a</test2>
>> </test>
>> <test>
>> <name>eel</name>
>> <test2>a</test2>
>> <test2>a</test2>
>> </test>
>></root>
>>
>>how would I do in XSL to output all test2 tags no matter how many there
>are?
>>
>>should this design be better?
>>
>><root>
>> <test>
>> <name>monkey</name>
>> <test2>
>> <test3>a</test3>
>> <test3>a</test3>
>> <test3>a</test3>
>> </test2>
>>
>> </test>
>> <test>
>> <name>monkey</name>
>> <test2>
>> <test3>a</test3>
>> <test3>a</test3>
>> <test3>a</test3>
>> <test3>a</test3>
>> <test3>a</test3>
>> </test2>
>>
>> </test>
>></root>
>>
>>how should I do to output all test 3 tags? no matter how many they are?
>>
>>I have tried to put one for-each loop in another for-each loop but that
>only
>>outputs one of the test3 tags, not all of them
>>
>><xsl:for-each select="root/test">
>> <xsl:value-of select="name"/>
>> <xsl:for-each select="root/test2">
>> <xsl:value-of select="test3"/>
>> </xsl:for-each>
>></xsl:for-each>
>>
>>I'd appreciate an answer
>>thanks alot!
>