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Thread: atoi

  1. #1
    Mikal Guest

    atoi


    Hello, my project calls for using nested loops only to accept, validate and
    convert date(yyyymmdd) to european and us format style(dd/mm/yyyy and mm/dd/yyyy).
    we cannot use atoi to do this. my question is; how do i convert this to
    a numeric value?



  2. #2
    Alex Guest

    Re: atoi


    "Mikal" <kmpg@earthlink.net> wrote:
    >
    >Hello, my project calls for using nested loops only to accept, validate

    and
    >convert date(yyyymmdd) to european and us format style(dd/mm/yyyy and mm/dd/yyyy).
    > we cannot use atoi to do this. my question is; how do i convert this to
    >a numeric value?
    >
    >Hi, I'm Alex look how I'd do that:

    if the data is a numeric value (no caracters) how I wonderstand:
    int dd=0,mm=0,yyyy=0,date;
    char eur[11];
    dd=date%100;date\=100;
    mm=date%100;date\=100;
    yyyy=date;
    eur[0]=dd;
    eur[1]='/';
    eur[2]='mm';
    eur[3]='/';
    eur[4]=yyyy
    I don run this code bur the ideea is to chop the number with div and mod
    operators and put them into an array, and after that to test the array's
    components


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